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Functions Involving Radicals

Functions with radicals are a basic class of functions.





























Basic Square Root and Cube Root Functions $$f(x)=\sqrt{x} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, g(x)=\sqrt[3]{x}$$
$$D=[0,\infty) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, D=\mathbb{R}$$ $$R=[0,\infty) \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, R=\mathbb{R}$$.





























Example: Given $f(x)=\sqrt{x-2},$ complete the table below, sketch a graph of $f(x),$ and determine the domain $D$ and range $R$ of $f(x).$
$ \begin{array}{c|c} x & f(x) \\ \hline 2 & \\ \hline 3 & \\ \hline 6 & \\ \hline 11 & \\ \hline \end{array} $






























Graphing Square Root and Cube Root Functions Using Transformations

Example: Graph $f(x)=\sqrt{x-2}+3$






























Graphing Square Root and Cube Root Functions Using Transformations

Example: Graph $f(x)=\sqrt{x-2}+3$


Step 1: Identify prototype (parent) function: $p(x)=\sqrt{x}.$











Step 2: Perform shift of $2$ to the right: $y=\,$$\,\sqrt{x-2}.$











Step 3: Perform shift of $3$ upward: $y=$$\sqrt{x-2}$$\,+\,3$







































Transformations of $p(x)=\sqrt[n]{x}$: Vertical and Horizontal Shifts

The graph of $f(x)=\,$$\,\sqrt[n]{x-h}$$\,+\,k$ is the graph of $p(x)=\sqrt[n]{x}$ shifted to the right by $h$ and up by $k.$

The graph of $f(x)=\,$$\,\sqrt[n]{x-h}$$\,-\,k$ is the graph of $p(x)=\sqrt[n]{x}$ shifted to the right by $h$ and down by $k.$

The graph of $f(x)=\,$$\,\sqrt[n]{x+h}$$\,+\,k$ is the graph of $p(x)=\sqrt[n]{x}$ shifted to the left by $h$ and up by $k.$

The graph of $f(x)=\,$$\,\sqrt[n]{x+h}$$\,-\,k$ is the graph of $p(x)=\sqrt[n]{x}$ shifted to the left by $h$ and down by $k.$





























Graphing Square Root and Cube Root Functions Using Transformations

Example: $g(x)=\sqrt[3]{x+1}-2$






























Recap



$f(x)=$ $\sqrt{x-2}$ $+\,3\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$ $g(x)=$$\sqrt[3]{x+1}$ $-\,2$






























Graphs of Square Root and Cube Root Functions

Example: Write the formula for the function of each graph below.































Other Transformations: Stretching and Reflecting

Example: Graph $f(x)=-2\sqrt{x+3}+4.$



Step 1: Identify prototype (parent) function: $p(x)=\sqrt{x}.$











Step 2: Perform shift of $3$ to the left: $y=\,$$\,\sqrt{x+3}.$











Step 3: Perform stretch vertically by $2$: $y=$$\,2\,$$\sqrt{x+3}$











Step 3: Perform reflect over $x$-axis with $-$ sign: $y=$$\,-2\,$$\sqrt{x+3}$











Step 4: Perform shift of $4$ upward: $y=$ $-2$ $\sqrt{x+3}$$\,+\,4$







































Transformations of $p(x)=\sqrt[n]{x}$: Vertical Stretching and Flipping

The graph of $f(x)=\,$$a$$\,\sqrt[n]{x}$ is the graph of $p(x)=\sqrt[n]{x}$ vertically stretched by a factor of $a.$

The graph of $f(x)=\,$$-$$\,\sqrt[n]{x}$ is the graph of $p(x)=\sqrt[n]{x}$ reflected over the $x$-axis.

The graph of $f(x)=\,$$-a$$\,\sqrt[n]{x}$ is
the graph of $p(x)=\sqrt[n]{x}$ reflected over the $x$-axis and then vertically stretched by a factor of $a.$



























Order of Transformations

Generally speaking, when using transformations to graph a function, we work from the inside out.

When performing transformations on $p(x)=\sqrt[n]{x}:$

Perform horizontal shifts first.

Perform vertical stretching/flipping second.

Perform vertical shifts third.





























Example: Graph $g(x)=3 \sqrt[3]{x-1}+2$






























Recap



$f(x)=\,$$-2$ $\sqrt{x+3}$ $+\,4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,$ $g(x)=$$\,3\,$$\sqrt[3]{x-1}$ $+\,2$






























Example: Given $f(x)=\sqrt{3−x},$ complete the table below, sketch a graph of $f(x),$ and determine the domain $D$ and range $R$ of $f(x).$
$ \begin{array}{c|c} x & f(x) \\ \hline -6 & \\ \hline -1 & \\ \hline 2 & \\ \hline 3 & \\ \hline \end{array} $






























Question: How would we find the domain and range algebraically?





























Example: Algebraically determine the domain $D$ and range $R$ of $$f(x)=\sqrt{7-4x}.$$

Since the index of the radical is even, whatever is under the radical must be non-negative. So, $$ 7-4x\geq 0 $$ Then, $7\geq 4x$ so that $\displaystyle \frac{7}{4}\geq x,$ or $$ x \leq \frac{7}{4} $$ Thus, the domain is $$ D=\left(-\infty,\frac{7}{4}\right] $$



Example: Algebraically determine the domain $D$ and range $R$ of $$g(x)=\sqrt[3]{7x-3}.$$

Since the index of the radical is odd, any real number, including negative numbers, can go under the radical. So, $$ D=\mathbb{R}=(-\infty,\infty) $$